What is the integral from 0 to 6 of e^xsin(x) ?

The integral from 0 to 6 of e^xsin(x) is (-e^6cos(6)+e^6sin(6)+1)/2

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integral from 0 to 6 of e^xsin(x)

\int_{0}^{6} e^{x} sin (x) d x

\frac{- e ^{6} cos ( 6 ) + e ^{6} sin ( 6 ) + 1}{2}

Decimal Notation

- 249.54229 \dots

Solution steps

\int_{0}^{6} e^{x} sin (x) d x

Compute the indefinite integral:

\int e^{x} sin (x) d x = - \frac{e ^{x} cos ( x )}{2} + \frac{e ^{x} sin ( x )}{2} + C

Compute the boundaries:

\int_{0}^{6} e^{x} sin (x) d x = \frac{- e ^{6} cos ( 6 ) + e ^{6} sin ( 6 )}{2} - (- \frac{1}{2})

= \frac{- e ^{6} cos ( 6 ) + e ^{6} sin ( 6 )}{2} - (- \frac{1}{2})

Simplify

= \frac{- e ^{6} cos ( 6 ) + e ^{6} sin ( 6 ) + 1}{2}

y = 2 x, (1, 3)

\int sin (18 x) cos (13 x) d x

\int x^{2} \cdot x d x

(t - 1)^{2}

6 y^{^{''}} + y^{^{'}} - 2 y = 0, y (0) = 5, y^{^{'}} (0) = - 1

What is the integral from 0 to 6 of e^xsin(x) ?
The integral from 0 to 6 of e^xsin(x) is (-e^6cos(6)+e^6sin(6)+1)/2