What is the integral of (sqrt(x)+2) ?

The integral of (sqrt(x)+2) is 2/3 x^{3/2}+2x+C

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integral of (sqrt(x)+2)

\int (x + 2) d x

\frac{2}{3} x^{\frac{3}{2}} + 2 x + C

Solution steps

\int x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int 2 d x

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

\int 2 d x = 2 x

= \frac{2}{3} x^{\frac{3}{2}} + 2 x

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} + 2 x + C

3 x e^{- a x}

5 t^{2} y^{^{''}} + t y^{^{'}} - 12 y = 0

\int \frac{x ^{2}}{x ^{6} - 9} d x

(3, 0), (6, 2)

\frac{\partial}{\partial z} (\frac{1}{x ^{2} + y ^{2} + z ^{2}})

What is the integral of (sqrt(x)+2) ?
The integral of (sqrt(x)+2) is 2/3 x^{3/2}+2x+C