What is the derivative of 10(x^3-x)^4 ?

The derivative of 10(x^3-x)^4 is 40(x^3-x)^3(3x^2-1)

What is the first derivative of 10(x^3-x)^4 ?

The first derivative of 10(x^3-x)^4 is 40(x^3-x)^3(3x^2-1)

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derivative of

10 (x^{3} - x)^{4}

40 (x^{3} - x)^{3} (3 x^{2} - 1)

Solution steps

\frac{d}{d x} (10 (x^{3} - x)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d x} ((x^{3} - x)^{4})

Apply the chain rule:

4 (x^{3} - x)^{3} \frac{d}{d x} (x^{3} - x)

= 4 (x^{3} - x)^{3} \frac{d}{d x} (x^{3} - x)

\frac{d}{d x} (x^{3} - x) = 3 x^{2} - 1

= 10 \cdot 4 (x^{3} - x)^{3} (3 x^{2} - 1)

Simplify

= 40 (x^{3} - x)^{3} (3 x^{2} - 1)

\frac{d}{d x} (sin (9 cos (x)))

\int \frac{2}{1 + x ^{2}} d x

x \to - \infty lim (\frac{- 1}{x})

\int \frac{1}{x ^{2} 9 x ^{2} - 4} d x

\int x^{2} e^{x^{3} + 2} d x

What is the derivative of 10(x^3-x)^4 ?
The derivative of 10(x^3-x)^4 is 40(x^3-x)^3(3x^2-1)
What is the first derivative of 10(x^3-x)^4 ?
The first derivative of 10(x^3-x)^4 is 40(x^3-x)^3(3x^2-1)