What is the derivative of-4/(1-4x) ?

The derivative of-4/(1-4x) is -(16)/((1-4x)^2)

What is the first derivative of-4/(1-4x) ?

The first derivative of-4/(1-4x) is -(16)/((1-4x)^2)

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\frac{d}{d x} (- \frac{4}{1 - 4 x})

- \frac{16}{( 1 - 4 x ) ^{2}}

Solution steps

\frac{d}{d x} (- \frac{4}{1 - 4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (\frac{1}{1 - 4 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 4 \frac{d}{d x} ((1 - 4 x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 - 4 x ) ^{2}} \frac{d}{d x} (1 - 4 x)

= - \frac{1}{( 1 - 4 x ) ^{2}} \frac{d}{d x} (1 - 4 x)

\frac{d}{d x} (1 - 4 x) = - 4

= - 4 (- \frac{1}{( 1 - 4 x ) ^{2}} (- 4))

Simplify

- 4 (- \frac{1}{( 1 - 4 x ) ^{2}} (- 4)) : - \frac{16}{( 1 - 4 x ) ^{2}}

= - \frac{16}{( 1 - 4 x ) ^{2}}

\frac{1}{x - 1}, x = 7

y = x^{3} - 2 x^{2} + x + 7

(arcsin (x))^{^{'}}

\frac{\partial}{\partial x} (tan (x) y)

\frac{( s + 5 )}{s ^{2} + 5 s + 6}

What is the derivative of-4/(1-4x) ?
The derivative of-4/(1-4x) is -(16)/((1-4x)^2)
What is the first derivative of-4/(1-4x) ?
The first derivative of-4/(1-4x) is -(16)/((1-4x)^2)