What is the derivative of-ln(x^4) ?

The derivative of-ln(x^4) is -4/x

What is the first derivative of-ln(x^4) ?

The first derivative of-ln(x^4) is -4/x

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\frac{d}{d x} (- ln (x^{4}))

- \frac{4}{x}

Solution steps

\frac{d}{d x} (- ln (x^{4}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (ln (x^{4}))

Apply the chain rule:

\frac{1}{x ^{4}} \frac{d}{d x} (x^{4})

= \frac{1}{x ^{4}} \frac{d}{d x} (x^{4})

\frac{d}{d x} (x^{4}) = 4 x^{3}

= - \frac{1}{x ^{4}} \cdot 4 x^{3}

Simplify

- \frac{1}{x ^{4}} \cdot 4 x^{3} : - \frac{4}{x}

= - \frac{4}{x}

\int 1 + cos (π θ) d θ

\frac{x}{2}

\frac{2 s - 3}{2 s ^{2} - 8 s + 16}

f (x) = 4 x^{3} ln (x)

x \to 1 lim (tan (\frac{x}{2}))

What is the derivative of-ln(x^4) ?
The derivative of-ln(x^4) is -4/x
What is the first derivative of-ln(x^4) ?
The first derivative of-ln(x^4) is -4/x