What is the derivative of 4/(x^3) ?

The derivative of 4/(x^3) is -(12)/(x^4)

What is the first derivative of 4/(x^3) ?

The first derivative of 4/(x^3) is -(12)/(x^4)

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derivative of

\frac{4}{x ^{3}}

- \frac{12}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{4}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- 3 x^{- 3 - 1})

Simplify

4 (- 3 x^{- 3 - 1}) : - \frac{12}{x ^{4}}

= - \frac{12}{x ^{4}}

\frac{\partial}{\partial y} (y + x + 2)

\int \frac{( x + 3 )}{x ^{2} + 2 x} d x

13 + 4 t

t \cdot cos (2 t)

\frac{\partial}{\partial y} (y - 1)

What is the derivative of 4/(x^3) ?
The derivative of 4/(x^3) is -(12)/(x^4)
What is the first derivative of 4/(x^3) ?
The first derivative of 4/(x^3) is -(12)/(x^4)