What is the first derivative of e^x-2 ?

The first derivative of e^x-2 is e^x

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derivative of e^x-2

\frac{d}{d x} (e^{x} - 2)

e^{x}

Solution steps

\frac{d}{d x} (e^{x} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) - \frac{d}{d x} (2)

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (2) = 0

= e^{x} - 0

Simplify

= e^{x}

\int_{- 2}^{0} (x + 2) d x

f (x) = \frac{1}{5 x - 8}

f (x) = x^{2} - 2 x + 1, - 3, 1

y^{^{'''}} - 7 y^{^{''}} - y^{^{'}} + 7 y = 0

\int \frac{1}{tan ( 2 x )} d x