What is the derivative of (mx)/(bx+c) ?

The derivative of (mx)/(bx+c) is x/(bx+c)

What is the first derivative of (mx)/(bx+c) ?

The first derivative of (mx)/(bx+c) is x/(bx+c)

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derivative of

\frac{m x}{b x + c}

\frac{x}{b x + c}

Solution steps

\frac{d}{d m} (\frac{m x}{b x + c})

Treat

b, c, x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{x}{b x + c} \frac{d m}{d m}

Apply the common derivative:

\frac{d m}{d m} = 1

= \frac{x}{b x + c} \cdot 1

Simplify

= \frac{x}{b x + c}

\int (x + 5) 8 - x d x

\frac{\partial}{\partial x} (2 + 3 x y)

n = 0 \sum \infty (4 x^{2})^{n}

x \to π lim (9 sin (sin (x)))

\int \frac{4}{x + 2} d x

What is the derivative of (mx)/(bx+c) ?
The derivative of (mx)/(bx+c) is x/(bx+c)
What is the first derivative of (mx)/(bx+c) ?
The first derivative of (mx)/(bx+c) is x/(bx+c)