What is the tangent of (70)/x ?

The tangent of (70)/x is y=-(70)/(a_{0)^2}x+(140)/(a_{0)}

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tangent of (70)/x

tangent of

\frac{70}{x}

y = - \frac{70}{a _{0}^{2}} x + \frac{140}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{70}{a _{0}})

Find the slope of

y = \frac{70}{x} : \frac{d y}{d x} = - \frac{70}{x ^{2}}

Compute the slope of

y = \frac{70}{x}

x = a_{0} : m = - \frac{70}{a _{0}^{2}}

Find the line with slope m=

- \frac{70}{a _{0}^{2}}

and passing through

(a_{0}, \frac{70}{a _{0}}) : y = - \frac{70}{a _{0}^{2}} x + \frac{140}{a _{0}}

y = - \frac{70}{a _{0}^{2}} x + \frac{140}{a _{0}}

\int sin (30 x) d x

n = 1 \sum \infty \frac{1}{n + 3}

\int_{0}^{5} ln (x) d x

f (x) = x^{2} - 6, at x = - 5

x \to 0 lim (\frac{3 ^{x} - 1}{x ^{2}})

What is the tangent of (70)/x ?
The tangent of (70)/x is y=-(70)/(a_{0)^2}x+(140)/(a_{0)}