What is the derivative of log_{2}(x^2+1) ?

The derivative of log_{2}(x^2+1) is (2x)/(ln(2)(x^2+1))

What is the first derivative of log_{2}(x^2+1) ?

The first derivative of log_{2}(x^2+1) is (2x)/(ln(2)(x^2+1))

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derivative of

lo g_{2} (x^{2} + 1)

\frac{2 x}{ln ( 2 ) ( x ^{2} + 1 )}

Solution steps

\frac{d}{d x} (lo g_{2} (x^{2} + 1))

Apply log rule:

lo g_{a} (b) = \frac{ln ( b )}{ln ( a )}

= \frac{d}{d x} (\frac{ln ( x ^{2} + 1 )}{ln ( 2 )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{ln ( 2 )} \frac{d}{d x} (ln (x^{2} + 1))

Apply the chain rule:

\frac{1}{x ^{2} + 1} \frac{d}{d x} (x^{2} + 1)

= \frac{1}{x ^{2} + 1} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= \frac{1}{ln ( 2 )} \cdot \frac{1}{x ^{2} + 1} \cdot 2 x

Simplify

\frac{1}{ln ( 2 )} \cdot \frac{1}{x ^{2} + 1} \cdot 2 x : \frac{2 x}{ln ( 2 ) ( x ^{2} + 1 )}

= \frac{2 x}{ln ( 2 ) ( x ^{2} + 1 )}

f (x) = \frac{x}{x + 5}

y = 9 - 4 x, at x = - 1

\int_{0}^{\frac{π}{4}} 9 tan^{3} (x) d x

\frac{d}{d x} (\frac{5 x ^{4} + 3 x ^{3}}{4 x - 9})

e^{x} sin (x)

What is the derivative of log_{2}(x^2+1) ?
The derivative of log_{2}(x^2+1) is (2x)/(ln(2)(x^2+1))
What is the first derivative of log_{2}(x^2+1) ?
The first derivative of log_{2}(x^2+1) is (2x)/(ln(2)(x^2+1))