What is the tangent of y=3x^2-x^3,(1,2) ?

The tangent of y=3x^2-x^3,(1,2) is y=3x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=3x^2-x^3,(1,2)

tangent of

y = 3 x^{2} - x^{3}, (1, 2)

y = 3 x - 1

Solution steps

Find the slope of

y = 3 x^{2} - x^{3} : \frac{d y}{d x} = 6 x - 3 x^{2}

Compute the slope of

y = 3 x^{2} - x^{3}

(1, 2) : m = 3

Find the line with slope m=

3

and passing through

(1, 2) : y = 3 x - 1

y = 3 x - 1

\int (8 cos (x) + 9 sin (x)) d x

\int - \frac{1}{4} csc (8 t) d t

\frac{\partial}{\partial x} (x^{2} + y e^{x})

\int \frac{11 - 2 x}{x ^{2} + 9 x + 14} d x

\frac{2 x}{3 - cot ( x )}

What is the tangent of y=3x^2-x^3,(1,2) ?
The tangent of y=3x^2-x^3,(1,2) is y=3x-1