What is the integral of 1/136 x^3 ?

The integral of 1/136 x^3 is (x^4)/(544)+C

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integral of 1/136 x^3

\int \frac{1}{136} x^{3} d x

\frac{x ^{4}}{544} + C

Solution steps

\int \frac{1}{136} x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{136} \cdot \int x^{3} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= \frac{1}{136} \cdot \frac{x ^{4}}{4}

Simplify

\frac{1}{136} \cdot \frac{x ^{4}}{4} : \frac{x ^{4}}{544}

= \frac{x ^{4}}{544}

Add a constant to the solution

= \frac{x ^{4}}{544} + C

y = \frac{- 9 e ^{4 x}}{8 x + 3}

\int \frac{( x - 2 )}{x - 1} d x

n = 0 \sum \infty \frac{1}{n ^{2} + n}

\int \frac{x}{x ^{2} - 6 x} d x

y^{^{'}} + y = \frac{1}{1 + e ^{t}}