What is the derivative of f(x)=3x^2-3 ?

The derivative of f(x)=3x^2-3 is 6x

What is the first derivative of f(x)=3x^2-3 ?

The first derivative of f(x)=3x^2-3 is 6x

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derivative of

f (x) = 3 x^{2} - 3

6 x

Solution steps

\frac{d}{d x} (3 x^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (3)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (3) = 0

= 6 x - 0

Simplify

= 6 x

x y^{^{'}} = e^{y}

\int_{0}^{1} (x - x) d x

n = 1 \sum \infty \frac{- 1 ^{n}}{n !}

x^{8 c o s (x)}

x \to 1 - lim (1 - x^{3})

What is the derivative of f(x)=3x^2-3 ?
The derivative of f(x)=3x^2-3 is 6x
What is the first derivative of f(x)=3x^2-3 ?
The first derivative of f(x)=3x^2-3 is 6x