What is the integral of x/(6+pi) ?

The integral of x/(6+pi) is (x^2)/(2(6+pi))+C

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integral of x/(6+pi)

\int \frac{x}{6 + π} d x

\frac{x ^{2}}{2 ( 6 + π )} + C

Solution steps

\int \frac{x}{6 + π} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6 + π} \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= \frac{1}{6 + π} \cdot \frac{x ^{2}}{2}

Simplify

\frac{1}{6 + π} \cdot \frac{x ^{2}}{2} : \frac{x ^{2}}{2 ( 6 + π )}

= \frac{x ^{2}}{2 ( 6 + π )}

Add a constant to the solution

= \frac{x ^{2}}{2 ( 6 + π )} + C

\frac{d}{d x} ((x^{2}) \cdot ln (x))

f (x) = \frac{x ^{2}}{9 + 2 x}

\int_{0}^{1} π (x - x^{10}) d x

\frac{d}{d x} (3 x^{2} e^{x} + x^{3} e^{x})

4 x^{3} - 12 x^{2}

What is the integral of x/(6+pi) ?
The integral of x/(6+pi) is (x^2)/(2(6+pi))+C