What is the tangent of x^9,\at x=1 ?

The tangent of x^9,\at x=1 is y=9x-8

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tangent of x^9,\at x=1

tangent of

x^{9}, at x = 1

y = 9 x - 8

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

y = x^{9} : \frac{d y}{d x} = 9 x^{8}

Compute the slope of

y = x^{9}

x = 1 : m = 9

Find the line with slope m=

9

and passing through

(1, 1) : y = 9 x - 8

y = 9 x - 8

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