What is the first (sin(5t))^' ?

The first (sin(5t))^' is cos(5t)*5

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(sin(5t))^'

(sin (5 t))^{^{'}}

cos (5 t) \cdot 5

Solution steps

(sin (5 t))^{'}

Apply the chain rule:

cos (5 t) (5 t)^{'}

= cos (5 t) (5 t)^{'}

(5 t)^{'} = 5

= cos (5 t) \cdot 5

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