What is the limit as x approaches 0 of xln(1+1/x) ?

The limit as x approaches 0 of xln(1+1/x) is Does not exist

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limit as x approaches 0 of xln(1+1/x)

x \to 0 lim (x ln (1 + \frac{1}{x}))

Does not exist

Solution steps

x \to 0 lim (x ln (1 + \frac{1}{x}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x ln (1 + \frac{1}{x})) = 0

x \to 0 - lim (x ln (1 + \frac{1}{x})) =

Does not exist

= Does not exist

\frac{- 3 x + 12}{2 6 - x}

f (x) = (tan (\frac{1}{x}))^{s e c (\frac{1}{x})}

\int \frac{x}{( 1 + x ^{2} ) ^{y}} d x

\frac{d}{d x} ((x - 1) (x + 3))

n = 1 \sum \infty (0.2)^{n - 1}

What is the limit as x approaches 0 of xln(1+1/x) ?
The limit as x approaches 0 of xln(1+1/x) is Does not exist