What is the solution for (dy)/(dx)+y=-1,y(0)=1 ?

The solution for (dy)/(dx)+y=-1,y(0)=1 is y=2e^{-x}-1

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(dy)/(dx)+y=-1,y(0)=1

\frac{d y}{d x} + y = - 1, y (0) = 1

y = 2 e^{- x} - 1

Solution steps

\frac{d y}{d x} + y = - 1

Solve separable ODE:

y = 2 e^{- x} - 1

y = 2 e^{- x} - 1

2 x - 3

f (x) = 3 x + 4, at x = 4

f (x) = x^{4} - 32 x^{2} + 256, at (1,)

\int cos (θ) d θ

\int \frac{n}{n + 1} d n

What is the solution for (dy)/(dx)+y=-1,y(0)=1 ?
The solution for (dy)/(dx)+y=-1,y(0)=1 is y=2e^{-x}-1