What is the solution for y^'=((xy+2y))/((x+3)) ?

The solution for y^'=((xy+2y))/((x+3)) is y=(e^{x+c_{1}})/(x+3)

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y^'=((xy+2y))/((x+3))

y^{^{'}} = \frac{( x y + 2 y )}{( x + 3 )}

y = \frac{e ^{x + c_{1}}}{x + 3}

Solution steps

y^{'} (x) = \frac{( x y + 2 y )}{( x + 3 )}

Solve separable ODE:

y = \frac{e ^{x + c_{1}}}{x + 3}

y = \frac{e ^{x + c_{1}}}{x + 3}

\int (4 x) d x

\frac{d y}{d t} = \frac{2 t}{1 + t ^{2}} y + \frac{2}{1 + t ^{2}}

\frac{d}{d x} (9 - 2 x)

f (x) = x^{2} - 6 x + 1, at x = 1

f (x) = \frac{1}{ln ( x )}

What is the solution for y^'=((xy+2y))/((x+3)) ?
The solution for y^'=((xy+2y))/((x+3)) is y=(e^{x+c_{1}})/(x+3)