What is the derivative of f(x)=sec(-4x^2-3x+2) ?

The derivative of f(x)=sec(-4x^2-3x+2) is sec(-4x^2-3x+2)tan(-4x^2-3x+2)(-8x-3)

What is the first derivative of f(x)=sec(-4x^2-3x+2) ?

The first derivative of f(x)=sec(-4x^2-3x+2) is sec(-4x^2-3x+2)tan(-4x^2-3x+2)(-8x-3)

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derivative of

f (x) = sec (- 4 x^{2} - 3 x + 2)

sec (- 4 x^{2} - 3 x + 2) tan (- 4 x^{2} - 3 x + 2) (- 8 x - 3)

Solution steps

\frac{d}{d x} (sec (- 4 x^{2} - 3 x + 2))

Apply the chain rule:

sec (- 4 x^{2} - 3 x + 2) tan (- 4 x^{2} - 3 x + 2) \frac{d}{d x} (- 4 x^{2} - 3 x + 2)

= sec (- 4 x^{2} - 3 x + 2) tan (- 4 x^{2} - 3 x + 2) \frac{d}{d x} (- 4 x^{2} - 3 x + 2)

\frac{d}{d x} (- 4 x^{2} - 3 x + 2) = - 8 x - 3

= sec (- 4 x^{2} - 3 x + 2) tan (- 4 x^{2} - 3 x + 2) (- 8 x - 3)

\frac{d}{d x} (e^{- \frac{1}{x ^{7}}})

x \to 0 lim (tan (x^{2}) ln (x))

\int - sin^{2} (x) d x

\frac{d}{d x} (\frac{3 x ^{2} - 3}{- 2 x})

What is the derivative of f(x)=sec(-4x^2-3x+2) ?
The derivative of f(x)=sec(-4x^2-3x+2) is sec(-4x^2-3x+2)tan(-4x^2-3x+2)(-8x-3)
What is the first derivative of f(x)=sec(-4x^2-3x+2) ?
The first derivative of f(x)=sec(-4x^2-3x+2) is sec(-4x^2-3x+2)tan(-4x^2-3x+2)(-8x-3)