What is the derivative of (x^2/((x^2-1))) ?

The derivative of (x^2/((x^2-1))) is -(2x)/((x^2-1)^2)

What is the first derivative of (x^2/((x^2-1))) ?

The first derivative of (x^2/((x^2-1))) is -(2x)/((x^2-1)^2)

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\frac{d}{d x} (\frac{x ^{2}}{( x ^{2} - 1 )})

- \frac{2 x}{( x ^{2} - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{( x ^{2} - 1 )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( x ^{2} - 1 ) - \frac{d}{d x} ( x ^{2} - 1 ) x ^{2}}{( x ^{2} - 1 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x^{2} - 1) = 2 x

= \frac{2 x ( x ^{2} - 1 ) - 2 x x ^{2}}{( x ^{2} - 1 ) ^{2}}

Simplify

\frac{2 x ( x ^{2} - 1 ) - 2 x x ^{2}}{( x ^{2} - 1 ) ^{2}} : - \frac{2 x}{( x ^{2} - 1 ) ^{2}}

= - \frac{2 x}{( x ^{2} - 1 ) ^{2}}

f (x) = 4 - 3 ln (x), at x = 1

\int 5 e^{- 0.8 x} d x

y = 6 + 4 x csc (x)

n = 1 \sum \infty \frac{3}{( 4 n ^{2} - 1 )}

\frac{\partial}{\partial y} ((2 x + 3 y)^{10})

What is the derivative of (x^2/((x^2-1))) ?
The derivative of (x^2/((x^2-1))) is -(2x)/((x^2-1)^2)
What is the first derivative of (x^2/((x^2-1))) ?
The first derivative of (x^2/((x^2-1))) is -(2x)/((x^2-1)^2)