What is the solution for xy^'=y-sqrt(x^2+y^2) ?

The solution for xy^'=y-sqrt(x^2+y^2) is y=-(x^2}{2e^{c_{1}}}+\frac{e^{c_{1}})/2

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xy^'=y-sqrt(x^2+y^2)

x y^{^{'}} = y - x^{2} + y^{2}

y = - \frac{x ^{2}}{2 e ^{c_{1}}} + \frac{e ^{c_{1}}}{2}

Solution steps

x y^{'} (x) = y - x^{2} + y^{2}

Solve using substitution:

y = - \frac{x ^{2}}{2 e ^{c_{1}}} + \frac{e ^{c_{1}}}{2}

y = - \frac{x ^{2}}{2 e ^{c_{1}}} + \frac{e ^{c_{1}}}{2}

x y^{^{'}} = 2 y

n = 0 \sum \infty - 5

\int \frac{4 x ^{3} + 3}{x ^{4} + 3 x} d x

y^{^{''}} + 2 y^{^{'}} + y = 19 e^{- t}

\frac{d}{d x} (- 3 e^{x})

What is the solution for xy^'=y-sqrt(x^2+y^2) ?
The solution for xy^'=y-sqrt(x^2+y^2) is y=-(x^2}{2e^{c_{1}}}+\frac{e^{c_{1}})/2