What is the integral of (3^4+x^{15}) ?

The integral of (3^4+x^{15}) is 81x+(x^{16})/(16)+C

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integral of (3^4+x^{15})

\int (3^{4} + x^{15}) d x

81 x + \frac{x ^{16}}{16} + C

Solution steps

\int 3^{4} + x^{15} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3^{4} d x + \int x^{15} d x

\int 3^{4} d x = 81 x

\int x^{15} d x = \frac{x ^{16}}{16}

= 81 x + \frac{x ^{16}}{16}

Add a constant to the solution

= 81 x + \frac{x ^{16}}{16} + C

\int x^{2} a^{2} - x^{2} d x

f (x) = x^{3} - x

y^{^{''}} + 4 y^{^{'}} + 4 y = 64 cos (2 x)

\int (y - 2) d y

\frac{d}{d x} (\frac{cos ( 3 x )}{x})

What is the integral of (3^4+x^{15}) ?
The integral of (3^4+x^{15}) is 81x+(x^{16})/(16)+C