What is the tangent of y=(2x-1)(x+4),(1,5) ?

The tangent of y=(2x-1)(x+4),(1,5) is y=11x-6

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tangent of y=(2x-1)(x+4),(1,5)

tangent of

y = (2 x - 1) (x + 4), (1, 5)

y = 11 x - 6

Solution steps

Find the slope of

y = (2 x - 1) (x + 4) : \frac{d y}{d x} = 4 x + 7

Compute the slope of

y = (2 x - 1) (x + 4)

(1, 5) : m = 11

Find the line with slope m=

11

and passing through

(1, 5) : y = 11 x - 6

y = 11 x - 6

\frac{d}{d x} ((x^{3} - 2 x)^{x^{2} - 3})

\frac{d}{d x} (x^{2} e^{x} sin (x))

f (x) = \frac{x + 9}{x ^{2} - 7 x + 1}

\int x \cdot sin (x^{2}) d x

What is the tangent of y=(2x-1)(x+4),(1,5) ?
The tangent of y=(2x-1)(x+4),(1,5) is y=11x-6