What is the solution for (dy)/(dx)-e^{8x+y}=0 ?

The solution for (dy)/(dx)-e^{8x+y}=0 is y=-ln(-1/8 e^{8x}-c_{1})

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(dy)/(dx)-e^{8x+y}=0

\frac{d y}{d x} - e^{8 x + y} = 0

y = - ln (- \frac{1}{8} e^{8 x} - c_{1})

Solution steps

\frac{d y}{d x} - e^{8 x + y} = 0

Solve separable ODE:

y = - ln (- \frac{1}{8} e^{8 x} - c_{1})

y = - ln (- \frac{1}{8} e^{8 x} - c_{1})

\int x \cdot sin (2 a x) d x

cos (e^{x^{2 c o s (x)}})

\frac{d}{d x} (5 e^{- x} - 3 e^{- 5 x})

f (x) = (x^{2} + 1) \cdot e^{x - 1}

81 y^{^{''}} + 72 y^{^{'}} + 16 y = 0, y^{^{'}} (0) = - 1

What is the solution for (dy)/(dx)-e^{8x+y}=0 ?
The solution for (dy)/(dx)-e^{8x+y}=0 is y=-ln(-1/8 e^{8x}-c_{1})