What is the tangent of f(x)=-3cos(x),\at x=(3pi)/4 ?

The tangent of f(x)=-3cos(x),\at x=(3pi)/4 is y= 3/(sqrt(2))x+3/(sqrt(2))-(9pi)/(4sqrt(2))

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tangent of f(x)=-3cos(x),\at x=(3pi)/4

tangent of

f (x) = - 3 cos (x), at x = \frac{3 π}{4}

y = \frac{3}{2} x + \frac{3}{2} - \frac{9 π}{4 2}

Solution steps

Find the tangent point:

(\frac{3 π}{4}, \frac{3}{2})

Find the slope of

f (x) = - 3 cos (x) : \frac{df ( x )}{d x} = 3 sin (x)

Compute the slope of

f (x) = - 3 cos (x)

x = \frac{3 π}{4} : m = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(\frac{3 π}{4}, \frac{3}{2}) : y = \frac{3}{2} x + \frac{3}{2} - \frac{9 π}{4 2}

y = \frac{3}{2} x + \frac{3}{2} - \frac{9 π}{4 2}

\frac{d}{d x} (sin (w x))

\int 15 sec^{4} (x) d x

f (x) = x^{2} - 9, (- 5, 16)

tan (x) - 1

\int e^{x y} + x y e^{x y} d y

What is the tangent of f(x)=-3cos(x),\at x=(3pi)/4 ?
The tangent of f(x)=-3cos(x),\at x=(3pi)/4 is y= 3/(sqrt(2))x+3/(sqrt(2))-(9pi)/(4sqrt(2))