What is the solution for 3y+x^4(dy)/(dx)=2xy ?

The solution for 3y+x^4(dy)/(dx)=2xy is y=e^{-1/(x^2)+1/(x^3)+c_{1}}

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3y+x^4(dy)/(dx)=2xy

3 y + x^{4} \frac{d y}{d x} = 2 x y

y = e^{- \frac{1}{x ^{2}} + \frac{1}{x ^{3}} + c_{1}}

Solution steps

3 y + x^{4} \frac{d y}{d x} = 2 x y

Solve separable ODE:

y = e^{- \frac{1}{x ^{2}} + \frac{1}{x ^{3}} + c_{1}}

y = e^{- \frac{1}{x ^{2}} + \frac{1}{x ^{3}} + c_{1}}

\int \frac{7 x}{1 - x ^{2}} d x

y = cot (2) (cos (x))

\frac{d}{d x} (5^{x - 1})

G (t) = \frac{4 t}{t + 1}

f (x) = x^{2} + 5 x, at x = 4

What is the solution for 3y+x^4(dy)/(dx)=2xy ?
The solution for 3y+x^4(dy)/(dx)=2xy is y=e^{-1/(x^2)+1/(x^3)+c_{1}}