What is the sum from n=0 to infinity of (2/4)^n ?

The sum from n=0 to infinity of (2/4)^n is 2

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sum from n=0 to infinity of (2/4)^n

n = 0 \sum \infty (\frac{2}{4})^{n}

2

Solution steps

n = 0 \sum \infty (\frac{2}{4})^{n}

Apply Series Geometric Test:

2

= 2

\int 5 x + 12 d x

n = 0 \sum \infty n \cdot (\frac{1}{6})^{n}

x y^{^{'}} + 2 y - 2 x^{2} y^{2} = 0

f (x) = (2 x - 3)^{4} (x^{2} + x + 1)^{5}

\int \frac{1}{x ^{2} + 6 x + 13} d x

What is the sum from n=0 to infinity of (2/4)^n ?
The sum from n=0 to infinity of (2/4)^n is 2