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Popular >

derivative of f(x)=sqrt(x^2+6x-1)

Solution

derivative of

f (x) = x^{2} + 6 x - 1

Solution

\frac{x + 3}{x ^{2} + 6 x - 1}

Solution steps

\frac{d}{d x} (x^{2} + 6 x - 1)

Apply the chain rule:

\frac{1}{2 x ^{2} + 6 x - 1} \frac{d}{d x} (x^{2} + 6 x - 1)

= \frac{1}{2 x ^{2} + 6 x - 1} \frac{d}{d x} (x^{2} + 6 x - 1)

\frac{d}{d x} (x^{2} + 6 x - 1) = 2 x + 6

= \frac{1}{2 x ^{2} + 6 x - 1} (2 x + 6)

Simplify

\frac{1}{2 x ^{2} + 6 x - 1} (2 x + 6) : \frac{x + 3}{x ^{2} + 6 x - 1}

= \frac{x + 3}{x ^{2} + 6 x - 1}

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y^{^{'''}} - y^{^{''}} - y^{^{'}} + y = 5

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\int 7 cot^{5} (x) sin^{4} (x) d x

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\int_{0}^{1} \frac{36}{( 2 x + 1 ) ^{3}} d x

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\int \frac{1}{x} + \frac{1}{x ^{2}} + \frac{1}{x ^{3}} d x

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\int sin (2 x) sin (7 x) d x

Frequently Asked Questions (FAQ)

What is the derivative of f(x)=sqrt(x^2+6x-1) ?
The derivative of f(x)=sqrt(x^2+6x-1) is (x+3)/(sqrt(x^2+6x-1))
What is the first derivative of f(x)=sqrt(x^2+6x-1) ?
The first derivative of f(x)=sqrt(x^2+6x-1) is (x+3)/(sqrt(x^2+6x-1))