What is the integral of x^2*e^{-ax} ?

The integral of x^2*e^{-ax} is -e^{-ax} 1/a x^2+2/(a^3)(-ae^{-ax}x-e^{-ax})+C

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integral of x^2*e^{-ax}

\int x^{2} \cdot e^{- a x} d x

- e^{- a x} \frac{1}{a} x^{2} + \frac{2}{a ^{3}} (- a e^{- a x} x - e^{- a x}) + C

Solution steps

\int x^{2} e^{- a x} d x

Apply Integration By Parts

: - e^{- a x} \frac{1}{a} x^{2} - \int - e^{- a x} \frac{2}{a} x d x

= - e^{- a x} \frac{1}{a} x^{2} - \int - e^{- a x} \frac{2}{a} x d x

\int - e^{- a x} \frac{2}{a} x d x = - \frac{2}{a ^{3}} (- a e^{- a x} x - e^{- a x})

= - e^{- a x} \frac{1}{a} x^{2} - (- \frac{2}{a ^{3}} (- a e^{- a x} x - e^{- a x}))

Simplify

= - e^{- a x} \frac{1}{a} x^{2} + \frac{2}{a ^{3}} (- a e^{- a x} x - e^{- a x})

Add a constant to the solution

= - e^{- a x} \frac{1}{a} x^{2} + \frac{2}{a ^{3}} (- a e^{- a x} x - e^{- a x}) + C

\frac{1}{( x - 1 )}

x \to 2 lim (ln (\frac{x}{x ^{2} - 4}))

a y (e^{b y})

ln (- x)

\int \frac{12}{x ^{- 1} + 3} d x

What is the integral of x^2*e^{-ax} ?
The integral of x^2*e^{-ax} is -e^{-ax} 1/a x^2+2/(a^3)(-ae^{-ax}x-e^{-ax})+C