What is the solution for y^{''}-y^'-2y=8,y(0)=0,y^'(0)=5 ?

The solution for y^{''}-y^'-2y=8,y(0)=0,y^'(0)=5 is y=3e^{2t}+e^{-t}-4

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y^{''}-y^'-2y=8,y(0)=0,y^'(0)=5

y^{^{''}} - y^{^{'}} - 2 y = 8, y (0) = 0, y^{^{'}} (0) = 5

y = 3 e^{2 t} + e^{- t} - 4

Solution steps

y^{''} (t) - y^{'} (t) - 2 y = 8

Solve linear ODE:

y = 3 e^{2 t} + e^{- t} - 4

y = 3 e^{2 t} + e^{- t} - 4

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What is the solution for y^{''}-y^'-2y=8,y(0)=0,y^'(0)=5 ?
The solution for y^{''}-y^'-2y=8,y(0)=0,y^'(0)=5 is y=3e^{2t}+e^{-t}-4