What is the derivative of x^2+x-8 ?

The derivative of x^2+x-8 is 2x+1

What is the first derivative of x^2+x-8 ?

The first derivative of x^2+x-8 is 2x+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

x^{2} + x - 8

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (8) = 0

= 2 x + 1 - 0

Simplify

= 2 x + 1

\int 7 x arcsin (x) d x

x \to 0 lim (\frac{9}{x} - \frac{9}{∣ x ∣})

\int \frac{( sin ( ln ( x ) ) )}{x} d x

4 y^{^{''}} + 4 y^{^{'}} - 3 y = cos (2 x)

\int_{2}^{3} \frac{26}{3 - x} d x

What is the derivative of x^2+x-8 ?
The derivative of x^2+x-8 is 2x+1
What is the first derivative of x^2+x-8 ?
The first derivative of x^2+x-8 is 2x+1