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Popular >

y^{''}+25y^'=0

Solution

y^{^{''}} + 25 y^{^{'}} = 0

Solution

y = c_{1} + c_{2} e^{- 25 t}

Solution steps

y^{''} (t) + 25 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 25 t}

y = c_{1} + c_{2} e^{- 25 t}

Popular Examples

derivative of f(x)=7e^{x^2-5x+6}derivative of

f (x) = 7 e^{x^{2} - 5 x + 6}

integral of (10x+4)sqrt(5x^2+4x)

\int (10 x + 4) 5 x^{2} + 4 x d x

integral from 1 to 3 of ((ax)^3+e^{-bx})

\int_{1}^{3} ((a x)^{3} + e^{- b x}) d x

integral from 0 to 2 of 4x

\int_{0}^{2} 4 x d x

limit as x approaches 1 of sqrt(1-x)

x \to 1 lim (1 - x)

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+25y^'=0 ?
The solution for y^{''}+25y^'=0 is y=c_{1}+c_{2}e^{-25t}