What is the integral from 1 to 9 of 2/(x^3) ?

The integral from 1 to 9 of 2/(x^3) is 80/81

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integral from 1 to 9 of 2/(x^3)

\int_{1}^{9} \frac{2}{x ^{3}} d x

\frac{80}{81}

Decimal Notation

0.98765 \dots

Solution steps

\int_{1}^{9} \frac{2}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{9} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{9}

= 2 [- \frac{1}{2 x ^{2}}]_{1}^{9}

Compute the boundaries:

\frac{40}{81}

= 2 \cdot \frac{40}{81}

Simplify

= \frac{80}{81}

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What is the integral from 1 to 9 of 2/(x^3) ?
The integral from 1 to 9 of 2/(x^3) is 80/81