What is the integral of sin(x)*tan(x) ?

The integral of sin(x)*tan(x) is ln|tan(x)+sec(x)|-sin(x)+C

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integral of sin(x)*tan(x)

\int sin (x) \cdot tan (x) d x

ln ∣ tan (x) + sec (x) ∣ - sin (x) + C

Solution steps

\int sin (x) tan (x) d x

Rewrite using trig identities

= \int \frac{1 - cos ^{2} ( x )}{cos ( x )} d x

Expand

\frac{1 - cos ^{2} ( x )}{cos ( x )} : \frac{1}{cos ( x )} - cos (x)

= \int \frac{1}{cos ( x )} - cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{cos ( x )} d x - \int cos (x) d x

\int \frac{1}{cos ( x )} d x = ln ∣ tan (x) + sec (x) ∣

\int cos (x) d x = sin (x)

= ln ∣ tan (x) + sec (x) ∣ - sin (x)

Add a constant to the solution

= ln ∣ tan (x) + sec (x) ∣ - sin (x) + C

\int_{0}^{1} π (5 x^{2})^{2} d x

\int x - csc (x) cot (x) d x

\int (sin (7 x)) d x

\frac{d}{d x} (\frac{1}{2} ln (2 x))

\frac{d y}{d t} = (15 - \frac{3 y}{360 - 2 t})

What is the integral of sin(x)*tan(x) ?
The integral of sin(x)*tan(x) is ln|tan(x)+sec(x)|-sin(x)+C