What is the integral of (3x^2-2)/(x^2-2x-8) ?

The integral of (3x^2-2)/(x^2-2x-8) is 3x-5/3 ln|x+2|+23/3 ln|x-4|+C

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integral of (3x^2-2)/(x^2-2x-8)

\int \frac{3 x ^{2} - 2}{x ^{2} - 2 x - 8} d x

3 x - \frac{5}{3} ln ∣ x + 2 ∣ + \frac{23}{3} ln ∣ x - 4 ∣ + C

Solution steps

\int \frac{3 x ^{2} - 2}{x ^{2} - 2 x - 8} d x

Take the partial fraction of

\frac{3 x ^{2} - 2}{x ^{2} - 2 x - 8} : 3 - \frac{5}{3 ( x + 2 )} + \frac{23}{3 ( x - 4 )}

= \int 3 - \frac{5}{3 ( x + 2 )} + \frac{23}{3 ( x - 4 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 d x - \int \frac{5}{3 ( x + 2 )} d x + \int \frac{23}{3 ( x - 4 )} d x

\int 3 d x = 3 x

\int \frac{5}{3 ( x + 2 )} d x = \frac{5}{3} ln ∣ x + 2 ∣

\int \frac{23}{3 ( x - 4 )} d x = \frac{23}{3} ln ∣ x - 4 ∣

= 3 x - \frac{5}{3} ln ∣ x + 2 ∣ + \frac{23}{3} ln ∣ x - 4 ∣

Add a constant to the solution

= 3 x - \frac{5}{3} ln ∣ x + 2 ∣ + \frac{23}{3} ln ∣ x - 4 ∣ + C

\int (y - 4)^{2} d y

\frac{d}{d x} (\frac{x ^{2}}{x - 6})

\frac{\partial}{\partial x} (\frac{x y}{1 + x y ^{2}})

\int \frac{( sin ( x ) ) ^{2}}{( cos ( x ) ) ^{4}} d x

\int_{1}^{4} \frac{e ^{\frac{4}{x}}}{x ^{2}} d x

What is the integral of (3x^2-2)/(x^2-2x-8) ?
The integral of (3x^2-2)/(x^2-2x-8) is 3x-5/3 ln|x+2|+23/3 ln|x-4|+C