What is (\partial)/(\partial z)(e^xsin(yz)) ?

The answer to (\partial)/(\partial z)(e^xsin(yz)) is e^xcos(yz)y

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(\partial)/(\partial z)(e^xsin(yz))

\frac{\partial}{\partial z} (e^{x} sin (yz))

e^{x} cos (yz) y

Solution steps

\frac{\partial}{\partial z} (e^{x} sin (yz))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{x} \frac{\partial}{\partial z} (sin (yz))

Apply the chain rule:

cos (yz) \frac{\partial}{\partial z} (yz)

= cos (yz) \frac{\partial}{\partial z} (yz)

\frac{\partial}{\partial z} (yz) = y

= e^{x} cos (yz) y

\int 10 sin^{3} (x) cos^{7} (x) d x

\frac{\partial}{\partial x} (y^{2} - e^{x y})

\frac{s}{s ^{4} + 1}

\int tan (2 t) d t

y^{^{''}} + 16 y = t e^{4 t}

What is (\partial)/(\partial z)(e^xsin(yz)) ?
The answer to (\partial)/(\partial z)(e^xsin(yz)) is e^xcos(yz)y