What is the derivative of ln(9x^2) ?

The derivative of ln(9x^2) is 4ln(3)x

What is the first derivative of ln(9x^2) ?

The first derivative of ln(9x^2) is 4ln(3)x

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\frac{d}{d x} (ln (9) x^{2})

4 ln (3) x

Solution steps

\frac{d}{d x} (ln (9) x^{2})

Simplify

ln (9) x^{2} : 2 ln (3) x^{2}

= \frac{d}{d x} (2 ln (3) x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 ln (3) \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 ln (3) \cdot 2 x^{2 - 1}

Simplify

= 4 ln (3) x

x \to - 8 - lim (\frac{- 5 x}{x + 8})

\int_{3}^{9} (1 + x^{2}) d x

\int \frac{24}{( x - 2 ) ( x ^{2} + 4 )} d x

\int_{0}^{1} \frac{x ^{2}}{x ^{3} - 1} d x

y = e^{5 x}

What is the derivative of ln(9x^2) ?
The derivative of ln(9x^2) is 4ln(3)x
What is the first derivative of ln(9x^2) ?
The first derivative of ln(9x^2) is 4ln(3)x