What is the solution for y^{''}-y=10sin^2(x) ?

The solution for y^{''}-y=10sin^2(x) is y=c_{1}e^x+c_{2}e^{-x}-10sin^2(x)-4cos(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y=10sin^2(x)

y^{^{''}} - y = 10 sin^{2} (x)

y = c_{1} e^{x} + c_{2} e^{- x} - 10 sin^{2} (x) - 4 cos (2 x)

Solution steps

y^{''} (x) - y = 10 sin^{2} (x)

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- x} - 10 sin^{2} (x) - 4 cos (2 x)

y = c_{1} e^{x} + c_{2} e^{- x} - 10 sin^{2} (x) - 4 cos (2 x)

\int 2^{x} (2^{- x} + 1) d x

\int \frac{1}{x ^{2} + 100} d x

n = 0 \sum \infty (\frac{1}{10})^{n}

5 cos (\frac{t}{3000})

\int e^{- X} d X

What is the solution for y^{''}-y=10sin^2(x) ?
The solution for y^{''}-y=10sin^2(x) is y=c_{1}e^x+c_{2}e^{-x}-10sin^2(x)-4cos(2x)