What is the limit as p approaches 4 of sqrt(p^2+p+5) ?

The limit as p approaches 4 of sqrt(p^2+p+5) is 5

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limit as p approaches 4 of sqrt(p^2+p+5)

p \to 4 lim (p^{2} + p + 5)

5

Solution steps

p \to 4 lim (p^{2} + p + 5)

Plug in the value

p = 4

= 4^{2} + 4 + 5

Simplify

4^{2} + 4 + 5 : 5

= 5

e^{2 x} cos (5 x)

f (x) = \frac{6 x}{3 + x}

\frac{d}{d x} (144 - x^{2})

1 + x

x y^{^{'}} - y = \frac{2}{3} x ln (x)

What is the limit as p approaches 4 of sqrt(p^2+p+5) ?
The limit as p approaches 4 of sqrt(p^2+p+5) is 5