What is the derivative of y=-2x^2 ?

The derivative of y=-2x^2 is -4x

What is the first derivative of y=-2x^2 ?

The first derivative of y=-2x^2 is -4x

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derivative of

y = - 2 x^{2}

- 4 x

Solution steps

\frac{d}{d x} (- 2 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 \cdot 2 x^{2 - 1}

Simplify

= - 4 x

\frac{x ^{2}}{3 + 4 x}

t \cdot e^{- 3 t} \cdot sin (5 t)

\frac{x ^{2}}{5 + x}

- \frac{1}{( x - 1 ) ^{2}}

\int 2 sin (x) + cos (x) - 3 d x

What is the derivative of y=-2x^2 ?
The derivative of y=-2x^2 is -4x
What is the first derivative of y=-2x^2 ?
The first derivative of y=-2x^2 is -4x