What is the derivative of 35.4cos(0.1(x+6.2)) ?

The derivative of 35.4cos(0.1(x+6.2)) is -3.54sin(0.1(x+6.2))

What is the first derivative of 35.4cos(0.1(x+6.2)) ?

The first derivative of 35.4cos(0.1(x+6.2)) is -3.54sin(0.1(x+6.2))

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derivative of

35.4 cos (0.1 (x + 6.2))

- 3.54 sin (0.1 (x + 6.2))

Solution steps

\frac{d}{d x} (35.4 cos (0.1 (x + 6.2)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 35.4 \frac{d}{d x} (cos (0.1 (x + 6.2)))

Apply the chain rule:

- sin (0.1 (x + 6.2)) \frac{d}{d x} (0.1 (x + 6.2))

= - sin (0.1 (x + 6.2)) \frac{d}{d x} (0.1 (x + 6.2))

\frac{d}{d x} (0.1 (x + 6.2)) = 0.1

= 35.4 (- sin (0.1 (x + 6.2)) \cdot 0.1)

Simplify

= - 3.54 sin (0.1 (x + 6.2))

x \to 1.01 lim (\frac{1}{x ^{2} - 1})

\frac{d}{d x} (1 + 3 x + 9 x^{2})

f (x) = 5 x^{2}

(9 x^{2} + y - 1) d x - (14 y - x) d y = 0, y (1) = 0

\int_{0}^{1} (x + 1 - x^{2}) d x

What is the derivative of 35.4cos(0.1(x+6.2)) ?
The derivative of 35.4cos(0.1(x+6.2)) is -3.54sin(0.1(x+6.2))
What is the first derivative of 35.4cos(0.1(x+6.2)) ?
The first derivative of 35.4cos(0.1(x+6.2)) is -3.54sin(0.1(x+6.2))