What is (\partial)/(\partial x)(-x/(y^2)) ?

The answer to (\partial)/(\partial x)(-x/(y^2)) is -1/(y^2)

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(\partial)/(\partial x)(-x/(y^2))

\frac{\partial}{\partial x} (- \frac{x}{y ^{2}})

- \frac{1}{y ^{2}}

Solution steps

\frac{\partial}{\partial x} (- \frac{x}{y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{y ^{2}} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= - \frac{1}{y ^{2}} \cdot 1

Simplify

= - \frac{1}{y ^{2}}

\frac{s + 2}{s ^{2} + 2 s + 2}

x \to - 4 lim (7 - x)

\int_{- 2}^{2} x^{3} cos (\frac{x}{2}) d x

\int_{0}^{1} e^{- 0.2 x} d x

x \to \infty + lim (cos (x))

What is (\partial)/(\partial x)(-x/(y^2)) ?
The answer to (\partial)/(\partial x)(-x/(y^2)) is -1/(y^2)