What is laplacetransform 4-4*e^{2t} ?

The answer to laplacetransform 4-4*e^{2t} is 4/s-4/(s-2)

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laplacetransform 4-4*e^{2t}

laplace transform

4 - 4 \cdot e^{2 t}

\frac{4}{s} - \frac{4}{s - 2}

Solution steps

L {4 - 4 e^{2 t}}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {4} - 4 L {e^{2 t}}

L {4} : \frac{4}{s}

L {e^{2 t}} : \frac{1}{s - 2}

= \frac{4}{s} - 4 \cdot \frac{1}{s - 2}

Refine

\frac{4}{s} - 4 \frac{1}{s - 2} : \frac{4}{s} - \frac{4}{s - 2}

= \frac{4}{s} - \frac{4}{s - 2}

f (x) = \frac{e ^{x}}{x ^{2} + 1}

\int (7 x^{2}) e^{x^{3} + 1} d x

\int e^{- 2 y} y d y

f (x) = - x^{3} + x^{2} + 4 x - 2, at x = 0

\frac{\partial}{\partial y} (y e^{x y} sin (y))

What is laplacetransform 4-4*e^{2t} ?
The answer to laplacetransform 4-4*e^{2t} is 4/s-4/(s-2)