What is (\partial)/(\partial t)(y+xcos(t)) ?

The answer to (\partial)/(\partial t)(y+xcos(t)) is -xsin(t)

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(\partial)/(\partial t)(y+xcos(t))

\frac{\partial}{\partial t} (y + x cos (t))

- x sin (t)

Solution steps

\frac{\partial}{\partial t} (y + x cos (t))

Treat

y, x

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial t} (y) + \frac{\partial}{\partial t} (x cos (t))

\frac{\partial}{\partial t} (y) = 0

\frac{\partial}{\partial t} (x cos (t)) = - x sin (t)

= 0 - x sin (t)

Simplify

= - x sin (t)

\int 9 x^{2} d x

y^{^{''}} + 14 y^{^{'}} + 50 y = 0, y (0) = 2, y^{^{'}} (0) = - 17

y = (2 tan^{2} (2 x) - 1)^{\frac{1}{2}}

\frac{\partial}{\partial x} (x (1 - x - 2 y))

y^{'} = 0.002 y (2500 - y)

What is (\partial)/(\partial t)(y+xcos(t)) ?
The answer to (\partial)/(\partial t)(y+xcos(t)) is -xsin(t)