What is the integral of (3x^{8/3})/8+C ?

The integral of (3x^{8/3})/8+C is 9/88 x^{11/3}+Cx+C

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integral of (3x^{8/3})/8+C

\int \frac{3 x ^{\frac{8}{3}}}{8} + C d x

\frac{9}{88} x^{\frac{11}{3}} + C x + C

Solution steps

\int \frac{3 x ^{\frac{8}{3}}}{8} + C d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3 x ^{\frac{8}{3}}}{8} d x + \int C d x

\int \frac{3 x ^{\frac{8}{3}}}{8} d x = \frac{9}{88} x^{\frac{11}{3}}

\int C d x = C x

= \frac{9}{88} x^{\frac{11}{3}} + C x

Add a constant to the solution

= \frac{9}{88} x^{\frac{11}{3}} + C x + C

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What is the integral of (3x^{8/3})/8+C ?
The integral of (3x^{8/3})/8+C is 9/88 x^{11/3}+Cx+C