What is area y=9x^2ln(x),y=36ln(x) ?

The answer to area y=9x^2ln(x),y=36ln(x) is 4.27106…

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area y=9x^2ln(x),y=36ln(x)

area

y = 9 x^{2} ln (x), y = 36 ln (x)

4.27106 \dots

Solution steps

Apply the area formula:

\int_{1}^{2} 9 x^{2} ln (x) - 36 ln (x) d x

Solve

\int_{1}^{2} 9 x^{2} ln (x) - 36 ln (x) d x : 4.27106 \dots

The area is:

= 4.27106 \dots

cos^{2} (t)

x \to - 1 lim (x^{3} + x^{2} - 6 x + 9)

\int \frac{x}{( x + 2 ) ( 5 x - 1 )} d x

\frac{d ^{2}}{d x ^{2}} (tan (5 x + 2))

\int \frac{16 x}{( x ^{2} - 9 ) ^{5}} d x

What is area y=9x^2ln(x),y=36ln(x) ?
The answer to area y=9x^2ln(x),y=36ln(x) is 4.27106…