What is the solution for y^'=2y(1-0.2y) ?

The solution for y^'=2y(1-0.2y) is y=-(e^{2t+c_{1}})/(1-0.2e^{2t+c_{1)}}

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y^'=2y(1-0.2y)

y^{^{'}} = 2 y (1 - 0.2 y)

y = - \frac{e ^{2 t + c_{1}}}{1 - 0.2 e ^{2 t + c_{1}}}

Solution steps

y^{'} (t) = 2 y (1 - 0.2 y)

Solve separable ODE:

y = - \frac{e ^{2 t + c_{1}}}{1 - 0.2 e ^{2 t + c_{1}}}

y = - \frac{e ^{2 t + c_{1}}}{1 - 0.2 e ^{2 t + c_{1}}}

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What is the solution for y^'=2y(1-0.2y) ?
The solution for y^'=2y(1-0.2y) is y=-(e^{2t+c_{1}})/(1-0.2e^{2t+c_{1)}}