What is the derivative of 800-800x^{-1} ?

The derivative of 800-800x^{-1} is (800)/(x^2)

What is the first derivative of 800-800x^{-1} ?

The first derivative of 800-800x^{-1} is (800)/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (800 - 800 x^{- 1})

\frac{800}{x ^{2}}

Solution steps

\frac{d}{d x} (800 - 800 x^{- 1})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (800) - \frac{d}{d x} (800 x^{- 1})

\frac{d}{d x} (800) = 0

\frac{d}{d x} (800 x^{- 1}) = - \frac{800}{x ^{2}}

= 0 - (- \frac{800}{x ^{2}})

Simplify

= \frac{800}{x ^{2}}

\frac{\partial}{\partial t} (\frac{sin ( t )}{t})

n = 1 \sum \infty (0.1)^{n - 1}

\frac{\partial}{\partial x} (tan (4 x))

\frac{d}{d t} (t^{2} - t)

\frac{d ^{2}}{d x ^{2}} (2^{x})

What is the derivative of 800-800x^{-1} ?
The derivative of 800-800x^{-1} is (800)/(x^2)
What is the first derivative of 800-800x^{-1} ?
The first derivative of 800-800x^{-1} is (800)/(x^2)