What is the solution for x^'=(x-9)^2 ?

The solution for x^'=(x-9)^2 is x=-1/(t+c_{1)}+(9t)/(t+c_{1)}+(9c_{1})/(t+c_{1)}

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x^'=(x-9)^2

x^{^{'}} = (x - 9)^{2}

x = - \frac{1}{t + c _{1}} + \frac{9 t}{t + c _{1}} + \frac{9 c _{1}}{t + c _{1}}

Solution steps

x^{'} (t) = (x - 9)^{2}

Solve separable ODE:

x = - \frac{1}{t + c _{1}} + \frac{9 t}{t + c _{1}} + \frac{9 c _{1}}{t + c _{1}}

x = - \frac{1}{t + c _{1}} + \frac{9 t}{t + c _{1}} + \frac{9 c _{1}}{t + c _{1}}

6 x y

x \to 0 - lim ((- x)^{- x})

\frac{d}{d x} ((3 x^{3} - 2 x^{2}) \cdot (3 x^{4} + x^{2}))

\int \frac{20}{( x - 1 ) \cdot ( x ^{2} + 9 )} d x

y^{3} - 2 x - 2 d x + 3 y^{2} x d y = 0

What is the solution for x^'=(x-9)^2 ?
The solution for x^'=(x-9)^2 is x=-1/(t+c_{1)}+(9t)/(t+c_{1)}+(9c_{1})/(t+c_{1)}